已知:a2-b2=(a-b)(a+b);a3-b3=(a-b)(a2+ab+b2);a4-b4=(a-b)(a3+a2b+ab2+b3);按此规律,

2025-03-05 04:52:55
推荐回答(1个)
回答1:

(1)a4+a3b+a2b2+ab3+b4

(2)a3-
1
a3
=(a-
1
a
)(a2+1+
1
a2
),
=(a-
1
a
)(a2-2+
1
a2
+3),
=(a-
1
a
)[(a-
1
a
2+3],
=2×(4+3),
=2×7,
=14.