由a²+c²=b²+ac变形,得(a²+c²-b²)/2ac=1/2由余弦定理,得:cosB=1/2B=60°故A+C=120°由正弦定理a/c=sinA/sinC=sin(120°-C)/sinC==(√3+1)/2sin(120°-C)/sinC=(√3cosC/2+sinC/2)/sinC=√3cotC/2+1/2=(√3+1)/2解得:cotC=1C=45°