当x趋近于1时求(根号下(5x-4)-根号下x)⼀(根号下(x加3)-2)

2025-03-05 04:59:46
推荐回答(1个)
回答1:

当x趋近于1时求(根号下(5x-4)-根号下x)/(根号下(x加3)-2)
=当x趋近于1时求(根号下(5x-4)方-根号下x方)(根号下(x加3)+2)/(根号下(x加3)方-2方)(根号下(5x-4)+根号下x)
=lim(x->1) (4x-4)(根号下(x加3)+2)/(x-1)(根号下(5x-4)+根号下x)
=4lim(x->1) (根号下(x加3)+2)/(根号下(5x-4)+根号下x)
=4×(√4+2)/(√1+√1)
=4×4÷2
=8