在△ABC中,角A,B,C的对边分别为a,b,c,若(a+b+c)(sinA+sinB-sinC)=3asinB,则C=______°

2025-02-27 22:54:53
推荐回答(1个)
回答1:

由正弦定理可知(sinA+sinB+sinC)(sinA+sinB-sinC)=3sinAsinB
?(sinA+sinB) 2 -sin 2 C=3sinAsinB,
?sin 2 A+2sinAsinB+sin 2 B-sin 2 (A+B)=3sinAsinB,
?sin 2 A+sin 2 B-(sinAcosB+cosAsinB) 2 =sinAsinB,
?sin 2 A+sin 2 B-sin 2 A?cos 2 B-2sinAcosBcosAsinB-cos 2 A?sin 2 B=sinAsinB
?2sin 2 Asin 2 B-2sinAcosBsinBcosA=sinAsinB,
?cosAcosB-sinAsinB=-
1
2

∴cos(A+B)=-
1
2

∴A+B=
3

所以C=π-(A+B)=
π
3

故答案为:
π
3