答：切线y=-3x+m斜率k=y'(x)=-3y=x³-3x²求导：y'(x)=3x²-6x则有：k=y'(x)=3x²-6x=-3所以：x²-2x+1=0解得：x=1代入曲线得：y=1-3=-2切点(1,-2)代入直线y=-3x+m得：m=y+3x=-2+3=1所以：m=1
