1、4t/5,3t/5。2、∵∠PHQ=∠BAQ=90°,∴当两个三角形的两条直角边对应成比例时,两三角形相似。当H在Q左侧,即0①、当PH:AQ=HQ:AB时,可得:3t/5 : 4t/5 = (4 - 4t/5 - 4t/5) : 3,解得:t1=35/32。②、当PH:AB=HQ:AQ时,可得:3t/5 : 3 = (4 - 4t/5 - 4t/5) : 4t/5,解得:t2=-5+5√2,t3=-5-5√2(舍去)当H在Q右侧,即5/2①、当PH:AQ=HQ:AB时,可得:3t/5 : 4t/5 = (4t/5 + 4t/5 - 4) : 3,解得:t4=125/32。②、当PH:AB=HQ:AQ时,可得:3t/5 : 3 = (4t/5 + 4t/5 - 4) : 4t/5,解得:t5=t6=5(舍去)