设随机变量x的概率密度函数为f(x),且f(x)=f(-x)

则对于任意实数a 有 F(-a)=1/2-积分0到a f(x)dx为什么?
2024-11-12 01:07:10
推荐回答(1个)
回答1:

因为f(x)是随机变量x的概率密度函数
所以 ∫f(x)d(x)│(x=- ∞ to +∞)=1

又因为 f(x)=f(-x)
所以 ∫f(x)d(x)│(x=- a to 0)=∫f(x)d(x)│(x=0 to a )
F(0)=∫f(x)d(x)│(x=- ∞ to 0)=∫f(x)d(x)│(x=0 to +∞ )=(1/2)*∫f(x)d(x)│(x=- ∞ to +∞)=1/2
F(-a)=∫f(x)d(x)│(x=- ∞ to -a)=∫f(x)d(x)│(x=- ∞ to 0)-∫f(x)d(x)│(x=- a to 0)=1/2-∫f(x)d(x)│(x=0 to a )