高数用洛必达求极限

高数用洛必达求极限第七题到第十题
2025-02-27 03:40:21
推荐回答(1个)
回答1:

lim(x→0) (x^sinx)
=lim(x→0) e^[ln(x^sinx)]
=lim(x→0) e^(sinxlnx)
=lim(x→0) e^[lnx/(1/sinx)]
=lim(x→0) e^[(1/x)/(-cosx/sin^2x)]
=lim(x→0) e^[-sinx/cosx]
=lim(x→0) e^(-tanx)
=1