编程序计算1-1⼀2!+1⼀3!-1⼀4!+……+(-1)^(n-1)*1⼀n!,精确度为0.000001

2025-02-28 14:50:03
推荐回答(3个)
回答1:

#include
#include
void main()
{
int n=1;
double temp=1.0,sum=1.0;
do
{
n=n+1;
temp=-temp/n;
sum+=temp;
}
while (fabs(temp)>=1e-6);
printf("sum=%f\n",sum);
}

回答2:

额额额

回答3:

丁兰,你是有多无聊哦