已知α∈(∏⼀2,∏),且cos(∏⼀4-α)=3⼀5,则cosα=

2025-02-26 17:07:39
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回答1:

α∈(π/2,π),α-π/4∈(π/4,3π/4)
cos(∏/4-α)=cos(α-π/4)=3/5>0
所以
α-π/4∈(π/4,π/2)
sin(α-π/4)=4/5
cosα = cos(α-π/4+π/4)
=cos(α-π/4)cos(π/4)-sin(α-π/4)sin(π/4)
=3/5*√2/2-4/5*√2/2
=-√2/10