共轭向量不好表示,我拍张图片给你,字不太好(*^__^*)
设: z1=2 e^ja z2= e^jb
|z1-z2| = |2 e^ja - e^jb|
= √[5-4cos(a-b)]=2
5-4cos(a-b)=4
cos (a-b)=1/4
a-b=arccos (1/4)
z1/z2=2e^j(a-b)
=2[cos(a-b)+jsin(a-b)]
=2(1/4+j√15/4)
=0.5(1 + j√15)