(2a-3)+(6a+1)i = -7+bi , 2a-3=-7,6a+1=b,a=-2,b=-11
5、(2a+i)(1+3i)=-7+bi2a+6ai+i+3i^2=-7+bi(2a-3)+(6a+1)i=-7+bi2a-3=-72a=-4a=-26a+1=b6×(-2)+1=b-11=bb=-11a-b=-2-(-11)=9选B。
图
(2a+i)(1+3i)=(2a-3)+(6a+1)i所以 2a-3=-7 a=-2 6a+1=b b=-11 a-b=9