2sin平方225度-cot330度*tan405度 怎么求!

2025-03-15 17:53:36
推荐回答(3个)
回答1:

2sin平方225度-cot330度*tan405度
=2sin²(180°+45°)-cot(360°-30°)tan(360°+45°)
=2sin²(45°)+cot(30°)tan(45°)
=1+√3*1
=1+√3

回答2:

2sin平方225度-cot330度*tan405=2sin^245度+cot30tan(45°)
=1+根号3

回答3:

2sin²225-cot330tan405
=2sin²(180+45)-cot(360-30)tan(360+45)
=2sin²45+cot30tan45
=2×1/2+根号下3×1
=1+根号下3