已知α∈(π⼀4,3π⼀4),β∈(0,π⼀4),cos(α-π⼀4)=3⼀5,sin(3π⼀4+β)=5⼀13,则sin(α+β)的值为??

2025-02-25 11:09:38
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回答1:

cos(α-π/4)=3/5,sin(α-π/4)=4/5(因为α∈(π/4,3π/4),所以α-π/4∈(0.π/2))
sin(3π/4+β)=5/13,cos(3π/4+β)=-12/13(因为β∈(0,π/4,所以3π/4+β∈(3π/4,π))
cos(α-π/4)sin(3π/4+β)+cos(3π/4+β)sin(α-π/4)=sin(α-π/4+3π/4+β)=sin(α+β+π/2)
=-33/65 sin(α+β)=56/65
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