f(x)=√3sin²x+sinxcosx-√3/2=√3{1-cos2x}/2+1/2sin2x-√3/2=sin(2x-π/3)f(π/4)=sin(2*π/4-π/3)=sin(π/6)=1/2x∈(0，π/2)2x-π/3=π/2时，最大值=1f(A)=f(B)=sin(2A-π/3)=sin(2B-π/3)=1/2
