1⼀√2-1+√3(√3-√6)+√8

2025-03-04 03:57:50
推荐回答(1个)
回答1:

① 1/(√2-1)+√3(√3﹣√6)+√8
=√2+1+3-3√2+2√2
=4

②[(2/3)x√9x+6x√(y/x)]+[(y√﹙x/y﹚﹣x²√(1/x)]
=2x√x+6√xy+√xy-x√x
=7√xy+x√x

③(1/10) √200 - 2√0.08 - 4√0.5 + (2/5)√72
=√2-2√(8/100)-4√(1/2)+2/5√(2*36)
=√2-2/5√2-2√2+12/5√2
=√2