最简短的完整程序:
CODE SEGMENT
ASSUME CS:CODE
START:
;---------------------------------
MOV AX, 0
MOV CX, 100
S: ADD AX, CX
LOOP S
;-----基本的,就上面四行----
MOV AH, 4CH
INT 21H
CODE ENDS
END START
mov cx,100
s:
mov ax,0
mov bx,0
add ax,bx
inc bx
loop s
code segment
assume cs:code
start:mov cx,100
mov bx,1
mov ax,0
s: add ax,bx
inc bx
loop s
mov ax,4c00h
int 21h
code ends
end start
zhxinju123 | 一级 顺序有问题~~
mov cx,100
mov bx,0
mov ax,0
s:
add ax,bx
inc bx
loop s