∫(x^3+1)⼀(1+x^2)dx的不定积分

2025-03-13 11:12:09
推荐回答(1个)
回答1:

∫(x^3+1)/(1+x^2)dx
=∫(x^3+x-x+1)/(1+x^2)dx
=∫xdx + ∫(-x)/(1+x^2)dx + ∫1/(1+x^2)dx
=(1/2)x² - (1/2)ln(1+x²) + arctan(x) +C