x-x的六次方-x的五次方+x的四次方-x的三次方+x的平方+x-1

2025-04-27 01:33:25
推荐回答(1个)
回答1:

解:原式 = - x^6 - x^5 + x^4 - x^3 + x^2 + 2x - 1
= - x^6 - x^5 + x^4 +x^3 - 2x^3 - 2x^2 + 2x^2 + 2x + x^2 - 1
= - x^5(x+1) + x^3(x+1) - 2x^2(x+1) + 2x(x+1) + (x-1)(x+1)
= - (x+1)( x^5 - x^3 + 2x^2 - 3x +1)