linux中2个文件进行同行合并

2025-03-20 05:25:45
推荐回答(1个)
回答1:

#/bin/bash
count1=`cat file1|wc -l`
count2=`cat file2|wc -l`
a=`expr $count1 - $count2`
if [ $a -gt 0 ];then
for((i=1;i<=$count2;i++))
do
x=${i}"p"
echo "`cat file1|sed -n "$x"` `cat file2|sed -n "$x"`" >>/result.log
done
count=`expr $count2 + 1`
for((j=$count;j<=$count1;j++))
do
y=${j}"p"
z=${count2}"p"
echo "`cat file1|sed -n "$y"` `cat file2|sed -n "$z"`" >>/result.log
done
elif [ $a -lt 0 ];then
for((i=1;i<=$count1;i++))
do
x=${i}"p"
echo "`cat file2|sed -n "$x"` `cat file1|sed -n "$x"`" >>/result.log
done
count=`expr $count1 + 1`
for((j=$count;j<=$count2;j++))
do
y=${j}"p"
z=${count1}"p"
echo "`cat file2|sed -n "$y"` `cat file1|sed -n "$z"`" >>/result.log
done
else
for((k=1;k<=$count1;k++))
do
f=${k}"p"
echo "`cat file1|sed -n "$f"` `cat file2|sed -n "$f"`" >>/result.log
done
fi
行数小的写在行数大的后面,同行的话直接第二个文件内容写在第一个后面