求不定积分∫x⼀√(4-x눀) dx

2025-02-28 19:22:07
推荐回答(1个)
回答1:

∫x/√(4-x^2)dx
=-(1/2)∫d(4-x^2)/√(4-x^2)
=-(1/4)√(4-x^2)+C