求40+(x-60)*0.2=60+(x-200)*0.3

2025-02-27 06:36:08
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回答1:

40+(x-60)*0.2=60+(x-200)*0.3
40+0.2x-12=60+0.3x-60
0.3x-0.2x=40-12
0.1x=28
x=28÷0.1
x=280