1⼀sinx的不定积分是多少?麻烦给个过程

2025-02-25 12:36:38
推荐回答(1个)
回答1:

∫ dx/sinx
=∫ dx/(2*sin(x/2)*cos(x/2))
=∫ d(x/2)/(sin(x/2)*cos(x/2))
=∫ (d(x/2)/cos^2(x/2)) / (sin(x/2)/cos(x/2))
=∫ d(tan(x/2)) / tan(x/2)
=ln | tan(x/2) | +C
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