如图所示,灯L上标有“6V3W”字样,开关S闭合,滑片P移至a端时,电流表的示数为1A,且灯L正常发光.(1)

2025-04-28 19:35:10
推荐回答(1个)
回答1:

(1)开关S闭合,滑片P移至a端时,滑动变阻器都被连入电路,灯泡和变阻器并联,
因为灯泡正常发光,
则电源电压为:U=U =U L额 =6V,
∴通过灯泡的电流为:I L额 =
P L额
U L额
=
3W
6V
=0.5A,
则通过变阻器的电流为:I =I-I L额 =1A-0.5A=0.5A,
∴滑动变阻器的最大阻值为:R =
U
I
=
6V
0.5A
=12Ω.
(2)当开关断开,滑片P移至b端时,滑动变阻器都被连入电路,灯泡和变阻器串联,
而灯泡的电阻为:R L =
U L额 2
P 额L
=
(6V) 2
3W
=12Ω,
而此时电路中的电流为:I′=0.25A,
∴灯泡的实际功率为:P =I′ 2 R L =(0.25A) 2 ×12Ω=0.75W.
(3)∵t=1min=60s,
∴灯泡消耗的电能为:W=P t=0.75W×60s=45J.
答:(1)电源电压为6V,滑动变阻器的最大阻值为12Ω.
(2)此时灯泡的实际功率为0.75W.
(3)在1min内灯泡消耗的电能为45J.