高中数学必修4三角函数,求过程

2025-04-15 17:12:22
推荐回答(1个)
回答1:

f(5)=(asin5+b*5^3)/(ccos5)+3=-2
所以 (asin5+b*5^3)/(ccos5)=-5
f(-5)=(-asin5-b*5^3)/(ccos5)+3
=- (asin5+b*5^3)/(ccos5)+3
=8