设x.y为随机变量 且d(x+y)=7 d(x)=4 d(y)=1则cov(x.y)=

2025-02-25 11:19:52
推荐回答(1个)
回答1:

cov(X,Y)=E[(X-EX)(Y-EY)]
=E[XY]-EX*EY

d(X+Y)=E[(X+Y)^2-(E(X+Y))^2]
=E[X^2]-(EX)^2+E[Y^2]-(EY)^2+2(E[XY]-EX*EY)
=d(X)+d(Y)+2cov(X,Y)

故cov(X,Y)=1