Acosx+Bcosx=√(A²+B²)sin(x+φ) (tanφ=B/A)
√3/2cosx+1/2sinx=√[(√3/2)²+(1/2)²)sin(x+φ) =sin(x+φ)
∵tanφ=√3/3
∴φ=π/6
∴√3/2cosx+1/2sinx=sin(x+π/6)
此类问题用：Acosx+Bcosx=√(A²+B²)sin(x+φ) (tanφ=B/A)
√3/2cosx+1/2sinx=√[(√3/2)²+(1/2)²)sin(x+φ) =sin(x+φ)
∵tanφ=√3/3
∴φ=π/6
∴√3/2cosx+1/2sinx=sin(x+π/6)
sin(π/6)=1/2；cos(π/6)=√3/2
∴√3/2*sinx+1/2*cosx
=cos(π/6)sinx+sin(π/6)cosx
=sin(x+π/6)
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