13问答网 > (2+1)(2눀+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)的值为多少? 要过程.谢谢

(2+1)(2눀+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)的值为多少? 要过程.谢谢

2025-03-07 08:53:47

推荐回答（1个）

回答1：

(2+1)(2²+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)
=(2-1)(2+1)(2²+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)
=(2²-1)(2²+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)
=(2^4 -1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)
=(2^8 -1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)
=(2^16 -1)(2^16+1)(2^32+1)(2^64+1)
=(2^32-1)(2^32+1)(2^64+1)
=(2^64 -1)(2^64+1)
=2^128 -1