假设四位数为s=2345
int s; //s=2345int s1=s/1000 ; //s1=2int s2=s/100-s1*10; //s2=3int s3=s/10-s1*100-s2*10 //s3=4int s4=s-s1*1000-s2*100-s3*10 //s4=5int a=1000*s4+100*s3+10*s2+s1; //a=5432
请采纳，谢谢
