（1）√48÷√3-√1\2×√12+√24 =4-√2/2*2√2+2√6 =4-2+2√6 =2+2√6（2）√0.5+√12-(√1\3-√4又1\2) =√2/2+2 √3- (√3/3-3√2/2) =2√2+5/3*√3 .
