(22221/33332)/(44443/66665) = (22221*66665)/(33332*44443) = [(11111*6-1)(11111*2-1)]/[(11111*3-1)(11111*4-1)]= （11111*12+1-11111*8）/（11111*12+1-11111*7）<1后者大
22221/33332<44443/66665
