为什么旋转的水桶里的水面形状是抛物面给个物理回答

2025-03-17 05:25:47
推荐回答(3个)
回答1:

这叫离心现象。
作圆周运动的物体,由于本身的惯性,总是具有沿圆周切线飞出的趋势,其之只所以没有飞出去,是因为有向心力使作用迫使它不断地改变运动方向,使它同圆心的距离保持不变。一旦向心力消失,物体就会沿切线飞出,远离圆心而去。或是向心力不足,物体也将逐渐远离圆心。
例如,在雨中当你转动雨伞的伞柄时,雨伞上的水滴就会沿伞缘的切线方向飞出。除了向心力突然消失这种情况外,如果合力不足以提供使物体作圆周运动所需的向心力,物体也会逐渐远离圆心,这时物体就会沿着切线和圆周之间的某条曲线运动,也会离圆心越来越远。

回答2:

旋转的水桶里的水面形状是抛物面
需要大学微分方程证明,取液面底为原点建立坐标,在液面上取一质量元,其受重力和周围流体对的压力,它们的合力F就是使绕轴转动的向心力.
dF=dmgtan(A)=dmω^2x tan(A)=dy\dx
dmω^2x=dy\dx
即积分得,
y=(ω^2\2y)x^2,显然液面是一个抛物面付出,如果你看不懂,说明大学微积分没学,还是采纳吧

回答3:

分母部分的2y应为2g

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