解：原式=（x+1)/x÷[-(x+4)/(x-1)-(x²-x-2)/(x+1)(x-1)] =(x+1)/x÷[-(x²+5x+4+x²-x-2)/(x+1)(x-1)] =(x+1)/x÷[-(2x²+4x+2)/(x+1)(x-1)] =(x+1)/x*[-(x+1)(x-1)/2(x+1)²] =-(x-1)/2x
