∵∠AOD-∠BOD=50∴∠AOD=∠BOD+50∵AB为直线∴∠AOD+∠BOD=∠AOB=180∴∠BOD+50+∠BOD=180∴∠BOD=65∵∠AOC与∠BOD为对顶角∴∠AOC=∠BOD=65∵OE平分∠AOC∴∠AOE=1/2∠AOC=32.5∴∠BOE=180-∠AOE=180-32.5=147.5
解:∠A