把下列各式因式分解:(1)(x+2)(x+4)+1

2024-12-02 22:39:20
推荐回答(1个)
回答1:

:(1)(x+2)(x+4)+1
=x²+6x+8+1
=x²+6x+9
=(x+3)²

(2)4(a+b)²-9(a-b)²
=[2(a+b)+3(a-b)][2(a+b)-3(a-b)]
=(5a-b)(-a+5b)
=-(5a-b)(a-5b)

(3)x²(x-y)+2x(x-y)-(y-x)
=x²(x-y)+2x(x-y)+(x-y)
=(x-y)(x²+2x+1)
=(x-y)(x+1)²

(4)(x²+4)²-16x²
=(x²+4x+4)(x²-4x+4)
=(x+2)²(x-2)²

(5)(a+b)²+4(a+b+1)
=(a+b)²+4(a+b)+4
=(a+b+2)²