1、a²b+ab² = ab(a+b) = 432、a³b+ab³=ab(a²+b²) = ab[(a+b)²-2ab] = 7x[6²-2x7] = 154
a²b+ab² = ab(a+b) = 43 ;a³b+ab³=ab(a²+b²) = ab[(a+b)²-2ab] = 7x[6²-2x7] = 154请采纳