p =[0.0001 -0.0033 0.0497 -0.2746 1.6333 -74.3818]; f=@(x) -p*[x^5;x^4;x^3;x^2;x;1];[x,fval]=fmincon(f,10,[1;-1],[22;-4])结果为x = 22fval = -100.1684
可以用matlab求极值的函数fminunc试试
