At x meters (x in [0, 4]), the area of cross section is πr²
When the length is dx meters, the volume is πr²dx m³, the mass is ρ(x)πr²dx
See picture for the rest:
不小心漏了0.01π，结果应当乘以0.01π
M=∫(0,4)0.01π(3+√(2x))dx=0.12π+0.01(√2)π(2/3)4^(3/2)=0.12π+0.16(√2)π/3
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