解方程组2x+y=6,x-3y=1.求的7y(x-3y)的平方减2(3y-x)的三次方值

2025-05-01 02:56:56
推荐回答(2个)
回答1:

2x+y=6,
x-3y=1即2x-6y=2
7y=4,y=4/7,x=19/7
7y(x-3y)^2-2(3y-x)^3=7y*1^2-2(-1)^3=7y+1=5

回答2:

7y(x-3y)的平方减2(3y-x)的三次方
=7y(x-3y)²+2(x-3y)³
=(x-3y)²(7y+2(x-3y))
=7y+2x-6y
=2x+y
=6