计算: (2+1)(^2+1)(2^4+1)……(2^2n+1)+1

2025-02-25 22:21:57
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回答1:

原式=(2-1)(2+1)(2^2+1)(2^4+1)……(2^2n+1)+1
=(2^2-1)(2^2+1)(2^4+1)……(2^2n+1)+1
=(2^4-1)(2^4+1)……(2^2n+1)+1
=……
=(2^2n-1)(2^2n+1)+1
=2^4n-1+1
=2^4n