令S=1/2+(1/2)^2+1/3)^3+……+(1/2)^(n-1)+(1/2)^n
2S=1+1/2+(1/2)^2+……+(1/2)^(n-1)
S=2S-S=1-(1/2)^n
1/2+1/2^2+1/2^3+…+1/2^n
=1/2(1-1/2^n)/(1-1/2)
=1-1/2^n
等比数列求和
等比数列求和SN=a1*(1-q^n)/(1-q),其中a1=1/2,q=1/2,sn=(1/2)*(1-(1/2)^n)/(1-1/2)=1-(1/2)^n
令S=1/2+(1/2)^2+1/3)^3+……+(1/2)^(n-1)+(1/2)^n
2S=1+1/2+(1/2)^2+……+(1/2)^(n-1)
S=2S-S=1-(1/2)^n
或
1/2+1/2^2+1/2^3+…+1/2^n
=1/2(1-1/2^n)/(1-1/2)
=1-1/2^n
等比数列求和
等比数列求和
S=1-2的N次方分之一
1-1/2^n