已知非负实数a、b、c满足条件:3a+2b+c=4, 2a+b+3c=5,

2025-03-09 12:07:21
推荐回答(2个)
回答1:

3a+2b+c=4 (1)
2a+b+3c=5 (2)
(2)*2-(1)
a+5c=6
a=6-5c
a>=0,6-5c>=0
c<=6/5

(1)*2-(2)*3
b-7c=-7
b=7c-7>=0
c>=1
所以1<=c<=6/5

S=5a+4b+7c=5(6-5c)+4(7c-7)+7c
=10c+2
1<=c<=6/5
10<=10c<=12
12<=10c+2=S<=14
所以m=14,n=12
n-m=-2

回答2:

∵3a+2b+c=4, 2a+b+3c=5,∴a=6-5c,b=7c-7,∴S=5a+4b+7c=10c+2,
∵非负实数a、b、c∴a=6-5c≥0,b=7c-7≥0,∴1≤c≤65 ,∵S=10c+2,∴当c=65 时,
S最大=14,当c=1时,S最小=12,即m=14,n=12,∴n-m=-2