因式分解的两个题目 大家帮帮忙

要过程
2025-05-06 13:03:27
推荐回答(2个)
回答1:

1
原式=(4xyz)²-3²=(4xyz+3)(4xyz-3)

2
原式=[5(m+n+2)]²-[4(m-n-2)]²
=(5m+5n+10+4m-4n-8)(5m+5n+10-4m+4n+8)
=(9m+n+2)(m+9n+18)

回答2:

16x²y²z²-9
=(4xyz)²-3²
=(4xyz+3)(4xyz-3)

25(m+n+2)²-16(m-n-2)²
=[5(m+n+2)]²-[4(m-n-2)]²
=[5(m+n+2)+4(m-n-2)][5(m+n+2)-[4(m-n-2)]
=[5m+5n+10+4m-4n-8][5m+5n+10-4m+4n+8]
=[9m+n+2][m+9n+18]