求详细解答:电热水壶由于使用方便

2025-04-29 08:43:57
推荐回答(1个)
回答1:

解:(1) m =ρV = 1.0 × 10 3 kg/m 3 × 10 -3 m 3 = 1kg,            
Q =cm( t - t 0 )  =4.2 × 10 3 J/( kg . ℃) ×1 kg × (100℃ -20 ℃) = 3. 36 × 10 5 J.    
(2) W =Pt =2 000 W ×200 s =4 ×10 5 J.
=3.36 ×10 5 J/(4 ×10 5 J) =84%.