记函数f(x)=根号下2-[(x+3)⼀(x+1)]的定义域为A,g(x)=lg[(x-a-1)(2a-x)](a<1)的定义域为B.

(1)求A;(2)若B属于A,求实数a的取值范围.
2025-02-28 02:56:02
推荐回答(1个)
回答1:

1 2-[(x+3)/(x+1)]≥0
x-1/x+1≥0
-1<x≤1
2 (x-a-1)(2a-x)>0
[x-(a+1)](x-2a)<0
2a<x<a+1
∵B∈A
∴2a≥-1且a+1≤1
a≥-0.5且a≤0
∴-0.5≤a≤0