f(x)=sinxcosx= 1 2 sin2x,g(x)=cos2x= 1 2 cos2x+ 1 2 ,所以|AB|=|f(x)-g(x)|=| 1 2 sin2x-( 1 2 cos2x+ 1 2 )|= 2 2 |sin(2x- π 4 )- 2 2 |则sin(2x- π 4 )=-1时,|AB|的最大值为: 2 +1 2 .故答案为: 2 +1 2