若动直线x=a与函数f(x)=sinxcosx和g(x)=cos2x的图象分别交于M,N两点,则|MN|的最大值为2+122+12

2025-03-06 22:16:17
推荐回答(1个)
回答1:

f(x)=sinxcosx=
1
2
sin2x,g(x)=cos2x=
1
2
cos2x+
1
2

所以|AB|=|f(x)-g(x)|
=|
1
2
sin2x-(
1
2
cos2x+
1
2
)|
=
2
2
|sin(2x-
π
4
)-
2
2
|
则sin(2x-
π
4
)=-1时,
|AB|的最大值为:
2
+1
2

故答案为:
2
+1
2