%方法1linspace(0,1,10)%方法20:(1-0)/(10-1):1rand('state',0);A=rand(3,5)%全下标[i,j]=find(A>.5);%半下标k=find(A>.5);s=sign(randint(1,1000,[],123)-.5);n=sum(s==-1)A=rand(5);B1=A.^.5;B2=A^.5;%恢复A1=B1.^2;A2=B2^2;%比较all(reshape(A1==A2,1,[]))
2