求单片机八路抢答器的设计的C语言程序和仿真电路图

#include
#define uchar unsigned char
#define TIME 15
uchar table[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x40};
sbit rstkey=P3^2;
uchar cnt,sec;
uchar scanled,disdat[4]={0,10,0,0};
void t0isr() interrupt 1
{
	TH0=(65536-50000)/256;
	TL0=(65536-50000)%256;
	cnt++;
	if(cnt>=20)
		{
		cnt=0;
		if(sec>0)sec--;
		if(sec==0)TR0=0;
		}
	disdat[2]=sec/10;
	disdat[3]=sec%10;
}
void t1isr() interrupt 3
{
	TH1=(65536-5000)/256;
	TL1=(65536-5000)%256;
	P2=1<	P0=~table[disdat[scanled]];
	scanled++;
	scanled%=4;
}
main()
{
uchar key;
TMOD=0x11;
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
TH1=(65536-5000)/256;
TL1=(65536-5000)%256;
TR1=1;
ET0=1;
ET1=1;
EA=1;
	while(1)
	{
	while(1)
		{
		if(rstkey==0)break;//主持人按下复位键则开始
		}
		disdat[0]=0;
		sec=TIME;
		TR0=1;
	while(1)
		{
		key=P1;
		if(key!=0xff || sec==0)break;
		}
		TR0=0;
	switch(~key)
		{
		case 0x01:disdat[0]=1;break;
		case 0x02:disdat[0]=2;break;
		case 0x04:disdat[0]=3;break;
		case 0x08:disdat[0]=4;break;
		case 0x10:disdat[0]=5;break;
		case 0x20:disdat[0]=6;break;
		case 0x40:disdat[0]=7;break;
		case 0x80:disdat[0]=8;break;
		default:break;
		}
	}
}