c语言问题，求大佬帮忙

#include "stdafx.h"

#include

#define Sever_type 3

#define Oil_type 4

int oil_type;

int serve_type;

double ALL_Price;

struct OIL

{

char *type;

    double price;

};

struct SERVES

{

char *type;

double reduce;

};

OIL oil[4]={

{"90号汽油",6.95},

{"93号汽油",7.44},

{"97号汽油",7.93},

{"o错误",0.00},};

SERVES serve[3]={

{"m - 自助",0.05},

{"e - 协助",0.03},

{"s错误",0.00},};

void Prinf_Oil_message()

{

for(int i=0;i

{

printf("%s: 价格是%.2f \n",oil[i].type,oil[i].price);

}

for(int j=0;j

{

printf("%s: 优惠%.2f \n",serve[j].type,serve[j].reduce);

}

};

void Choice_serve_Oil(int ml,char S_type,int O_type)

{

int current_ml=ml;

switch(S_type)

{

    case 'm'  :

   serve_type=0;

       break; /* 可选的 */

    case 'e'  :

   serve_type=1;

       break; /* 可选的 */

    /* 您可以有任意数量的 case 语句 */

    default : 

serve_type=2;

printf("ERROR %s:PLS input again\n",serve[serve_type].type);   /* 可选的/* 可选的 */break;

}

switch(O_type)

{

    case 90  :

   oil_type=0;

       break; /* 可选的 */

    case 93  :

   oil_type=1;

       break; /* 可选的 */

case 97  :

   oil_type=2;

       break; /* 可选的 */

    /* 您可以有任意数量的 case 语句 */

    default :

   oil_type=3;

   printf("ERROR %s:PLS input again\n",oil[oil_type].type);   /* 可选的

*/break;

}

if(serve_type!=2&&oil_type!=3)

{

ALL_Price=current_ml*(1-serve[serve_type].reduce)*oil[oil_type].price;

printf("你的服务: %s，油: %s\n",serve[serve_type].type,oil[oil_type].type);

printf("总价格为%.2f，Welcome\n",ALL_Price);

}

};

int main(int argc, char* argv[])

{

int weight_kg=0;

char seversult;

int oilresult=0;

Prinf_Oil_message();

printf("Welcome Oilstation,Pls choice serves:\n");

while(true)

{

printf("PLS input: 重量(kg),服务(m or e),油型(90,93,97)\n");

    scanf("%d,%c,%d",&weight_kg,&seversult,&oilresult);

Choice_serve_Oil(weight_kg,seversult,oilresult);

}

return 0;

}

int main()
{
int a,b;
char c;
scanf("%d,%d,%c",&a,&b,&c);
float price;
float cost;
switch(b)
{
case 90:
price = 6.95;
break;
case 93:
price =7.44;
break;
case 97:
price = 7.93;
break;
default:
printf("无效汽油品种");
return 0;
}
if(c == 'm')
{
cost = price * a * 0.95;
}
else if(c == 'e')
{
cost = price * a * 0.97;
}
else
{
printf("错误服务类型");
return 0;
}
printf("%.2f\n",cost);
return 0;
}

我按照要求来搞定。