一道数学等差数列题,大家帮忙一下,谢谢!!!

2024-12-03 13:03:36
推荐回答(1个)
回答1:

Sn = (a2 + a(n-1)) * (n-3) / 2 + a1 + an = 209
又 a1 + an = a2 + a(n-1) = 19
代入得
19 + 19 * (n - 3) /2 = 209
n = 23
d = (a22 - a2) / (22 - 2) = 15/20 = 0.75